# If the Velocity of the Electron in Bohr’S First Orbit is 2.19 × 106 Ms–1, Calculate the De Broglie Wavelength Associated with It. - Chemistry

If the velocity of the electron in Bohr’s first orbit is 2.19 × 106 ms–1, calculate the de Broglie wavelength associated with it.

#### Solution

According to de Broglie’s equation,

lambda = h/(mv)

Where,

λ = wavelength associated with the electron

h = Planck’s constant

m = mass of electron

v = velocity of electron

Substituting the values in the expression of λ:

lambda = (6.626 xx 10^(-34) Js)/((9.10939 xx 10^(-31)kg)(2.19xx10^6 ms^(-1))

= 3.32 xx 10^(-10)m = 3.32 xx 10^(-10) mxx 100/100

= 332xx10^(-12) m

λ = 332 pm

∴Wavelength associated with the electron = 332 pm

Is there an error in this question or solution?

#### APPEARS IN

NCERT Class 11 Chemistry Textbook
Chapter 2 Structure of Atom
Q 59 | Page 68