Advertisement Remove all ads

If the Velocity of the Electron in Bohr’S First Orbit is 2.19 × 106 Ms–1, Calculate the De Broglie Wavelength Associated with It. - Chemistry

If the velocity of the electron in Bohr’s first orbit is 2.19 × 106 ms–1, calculate the de Broglie wavelength associated with it.

Advertisement Remove all ads

Solution

According to de Broglie’s equation,

`lambda = h/(mv)`

Where,

λ = wavelength associated with the electron

h = Planck’s constant

m = mass of electron

v = velocity of electron

Substituting the values in the expression of λ:

`lambda = (6.626 xx 10^(-34) Js)/((9.10939 xx 10^(-31)kg)(2.19xx10^6 ms^(-1))`

`= 3.32 xx 10^(-10)m = 3.32 xx 10^(-10) mxx 100/100`

`= 332xx10^(-12) m`

λ = 332 pm

∴Wavelength associated with the electron = 332 pm

  Is there an error in this question or solution?
Advertisement Remove all ads

APPEARS IN

NCERT Class 11 Chemistry Textbook
Chapter 2 Structure of Atom
Q 59 | Page 68
Advertisement Remove all ads
Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×