Question

If t_n = 2n – 5 is the nth term of an A.P., then find its first five terms

Answer 1

t_n = 2n – 5    ......[Given]

∴ t₁ = 2(1) – 5 = 2 – 5 = – 3

t₂ = 2(2) – 5 = 4 – 5 = – 1

t₃ = 2(3) – 5 = 6 – 5 = 1

t₄ = 2(4) – 5 = 8 – 5 = 3

t₅ = 2(5) – 5 = 10 – 5 = 5

∴ The first five terms of A.P. are – 3, – 1, 1, 3, 5.