If three lines whose equations are y = m1x + c1, y = m2x + c2 and y = m3x + c3 are concurrent, then show that m1(c2 – c3) + m2 (c3 – c1) + m3 (c1 – c2) = 0.
The equations of the given lines are
y = m1x + c1 … (1)
y = m2x + c2 … (2)
y = m3x + c3 … (3)
On subtracting equation (1) from (2), we obtain
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