**The question is based on a set of conditions. Choose the response that most accurately and completely answer the question.**

A science student has exactly four flasks - 1, 2, 3 and 4 - originally containing a red, a blue, a green, and an orange chemical, respectively. An experiment consists of mixing exactly two of these chemicals together by completely emptying the contents of one of the flasks into another of the flasks. The following conditions apply: The product of an experiment cannot be used in further experiments. Mixing the contents of 1 and 2 produces a red chemical. Mixing the contents of 2 and 3 produces an orange chemical. Mixing the contents of 3 with the contents of either 1 or 4 produces a blue chemical. Mixing the contents of 4 with the contents of either 1 or 2 produces a green chemical.

**If the student will perform exactly two experiments and after the first experiment exactly one of the resulting three non-empty flasks contains an orange chemical, then in the second experiment the student could mix together the contents of flasks**

#### Options

1 and 2

1 and 3

2 and 3

3 and 4

#### Solution

**3 and 4**

**Explanation:**

On the basis of given information, the arrangement is as follows:

No mix: 1 2 3 4

Red (R) Blue (B) Green (G) Orange (O)

Then, the rules they give in order...plus what is left in the other flasks... ‘–’ is the empty flask.

→ Mixing 1 and 2 produces Red

R – G O (2 into 1)

– R G O (1 into 2)

→ Mixing 2 and 3 produces Orange

R – O O (2 into 3)

R O – O (3 into 2)

→ Mixing 3 with either 1 or 4 produces Blue

B B – O (3 into 1)

R B – B (3 into 4)

→ Mixing 4 with either 1 or 2 produces Green

G B G – (4 into 1)

R G G – (4 into 2)

Simplifying the outcomes:

(R, G, O) (R, O, O) (B, B, O) (R, B, B) (G, B, G) And (R, G, G)

If the student will perform exactly two experiments and after the first experiment exactly one of the resulting three non-empty flasks contains an orange chemical then in the second experiment the student could mix together the content of flasks 3 and 4.