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Sum

If the replacement set is the set of natural numbers, solve: 4x + 1 ≥ 17

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#### Solution

4x + 1 ≥ 17

⇒ 4x + 1 - 1 ≥ 17 - 1 (Subtracting)

⇒ 4x ≥ 16

⇒ `"4x"/4` ≥ `16/4` (Dividing by 4)

⇒ x ≥ 4

Required answer = {4, 5, 6, ...}

Concept: Replacement Set and Solution Set

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