Sum

If the ordered pairs (x^{2} – 3x, y^{2} + 4y) and (– 2, 5) are equal, then find x and y

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#### Solution

(x^{2} – 3x, y^{2} + 4y) = (– 2, 5)

x^{2} – 3x = – 2

x^{2} – 3x + 2 = 0

(x – 2) (x – 1) = 0

x – 2 = 0 or x – 1 = 0

x = 2 or 1

y^{2} + 4y = 5

y^{2} + 4y – 5 = 0

(y + 5) (y – 1) = 0

y + 5 = 0 or y – 1 = 0

y = – 5 or y = 1

The value of x = 2, 1

and y = – 5, 1

Concept: Ordered Pair

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