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Sum

If the diagonals of a parallelogram are of equal lengths, the parallelogram is a rectangle. Prove it.

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#### Solution

**Given :** //gm ABCD in which AC = BD

**To Prove:** ABCD is rectangle.

**Proof :** In ∆ABC and ∆ABD

AB = AB (Common)

AC = BD (Given)

BC = AD (opposite sides of ||gm)

∆ABC = ∆ABD (S.S.S. Rule)

∠A = ∠B

But AD // BC (opp. sides of ||gm are ||)

∠A + ∠B = 180°

∠A = ∠B = 90°

Similarly ∠D = ∠C = 90°

Hence ABCD is a rectangle.

Is there an error in this question or solution?