# If the combination is connected to a battery of emf 20 V and negligible internal resistance, determine the current through each resistor, and the total current drawn from the battery. - Physics

Numerical

If the combination is connected to a battery of emf 20 V and negligible internal resistance, determine the current through each resistor, and the total current drawn from the battery.

#### Solution

Emf of the battery, V = 20 V

Current (I1) flowing through resistor R1 is given by,

I1 = "V"/"R"_1

= 20/2

= 10 A

Current (I2) flowing through resistor R2 is given by,

I2 = "V"/"R"_2

= 20/4

= 5 A

Current (I3) flowing through resistor R3 is given by,

I3 = "V"/"R"_3

= 20/5

= 4 A

Total current, I = I1 + I2 + I3 = 10 + 5 + 4 = 19 A

Therefore, the current through each resister is 10 A, 5 A, and 4 A respectively and the total current is 19 A.

Concept: Combination of Resistors - Series and Parallel
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#### APPEARS IN

NCERT Physics Part 1 and 2 Class 12
Chapter 3 Current Electricity
Exercise | Q 3.4 (b) | Page 127
NCERT Class 12 Physics Textbook
Chapter 3 Current Electricity
Exercise | Q 4.2 | Page 127

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