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Numerical

If the combination is connected to a battery of emf 20 V and negligible internal resistance, determine the current through each resistor, and the total current drawn from the battery.

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#### Solution

Emf of the battery, V = 20 V

Current (I_{1}) flowing through resistor R_{1} is given by,

I_{1} = `"V"/"R"_1`

= `20/2`

= 10 A

Current (I_{2}) flowing through resistor R_{2} is given by,

I_{2} = `"V"/"R"_2`

= `20/4`

= 5 A

Current (I_{3}) flowing through resistor R_{3} is given by,

I_{3} = `"V"/"R"_3`

= `20/5`

= 4 A

Total current, I = I_{1} + I_{2} + I_{3} = 10 + 5 + 4 = 19 A

Therefore, the current through each resister is 10 A, 5 A, and 4 A respectively and the total current is 19 A.

Concept: Combination of Resistors - Series and Parallel

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