# If the combination is connected to a battery of emf 12 V and negligible internal resistance, obtain the potential drop across each resistor. - Physics

Numerical

If the combination is connected to a battery of emf 12 V and negligible internal resistance, obtain the potential drop across each resistor.

#### Solution

Current flowing through the circuit = I

Emf of the battery, E = 12 V

Total resistance of the circuit, R = 6 Ω

The relation for current using Ohm’s law is,

I = "E"/"R"

= 12/6

= 2 A

Potential drop across 1 Ω resistor = V1

From Ohm’s law, the value of Vcan be obtained as

V1 = 2 × 1 = 2 V ..............(i)

Potential drop across 2 Ω resistor = V2

Again, from Ohm’s law, the value of Vcan be obtained as

V2 = 2 × 2 = 4 V …...........(ii)

Potential drop across 3 Ω resistor = V3

Again, from Ohm’s law, the value of Vcan be obtained as

V3 = 2 × 3 = 6 V …...........(iii)

Therefore, the potential drop across 1 Ω, 2 Ω, and 3 Ω resistors are 2 V, 4 V, and 6 V respectively.

Concept: Combination of Resistors - Series and Parallel
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#### APPEARS IN

NCERT Physics Part 1 and 2 Class 12
Chapter 3 Current Electricity
Exercise | Q 3.3 (b) | Page 127
NCERT Class 12 Physics Textbook
Chapter 3 Current Electricity
Exercise | Q 3.2 | Page 127

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