Answer 1

`sin (A – B) = 1/2` and `cos (A + B) = 1/2`

Now `sin (A - B) = 1/2`

`=> sin (A- B) = sin 30^@`

`=> A - B( = 30^@` ....(1)

And `cos (A + B) = 1/2`

`=> cos (A + B) = cos 60^@`

`=> A + B = 60^@` ...(2)

Adding (1) and (2) we get

`2A = 90^@`

`=> A = 90^@/2 = 45^@`

Put `A = 45^@` in (2 ) we get

`=> 45^@ + B = 60^@`

`=> B = 60^@ - 45^@``

`=>B = 15^@`

Thus `A = 45^@ and B = 15^@`