If the Product of Zeros of the Polynomial F(X) Ax3 − 6x2 + 11x − 6 is 4, Then a = - Mathematics

MCQ

If the product of zeros of the polynomial f(xax3 − 6x2 + 11x − 6 is 4, then a =

Options

• $\frac{3}{2}$

• $- \frac{3}{2}$

• $\frac{2}{3}$

• $- \frac{2}{3}$

• $- \frac{2}{3}$

Solution

Since alpha andbeta are the zeros of quadratic polynomial f(xax3 − 6x2 + 11x − 6

alpha + ß = - (text{coefficient of x})/(text{coefficient of } x^2)

So we have

4 = ((-6)/a)

4 = 6/a

4a=6

a = 6/4

a= (3xxcancel(2))/(2xxcancel(2))

a = 3/2

The value of a is 3/2

Hence, the correct alternative is (a).

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APPEARS IN

RD Sharma Class 10 Maths
Chapter 2 Polynomials
Q 11 | Page 62