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If the Product of Two Zeros of the Polynomial F(X) = 2x3 + 6x2 − 4x + 9 is 3, Then Its Third Zero is - Mathematics

MCQ

If the product of two zeros of the polynomial f(x) = 2x3 + 6x2 − 4x + 9 is 3, then its third zero is

Options

  • \[\frac{3}{2}\]

     

  • \[- \frac{3}{2}\]
  • \[\frac{9}{2}\]
  • \[- \frac{9}{2}\]
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Solution

Let αβγ  be the zeros of polynomial f(x) = 2x3 + 6x2 − 4x + 9 such that `alphabeta=3`

We have,

`alpha ß y= - (text{coefficient of x})/(text{coefficient of } x^2)`

`=(-9)/2`

Putting `alphabeta` in `alpha beta y`, we get

`alpha beta y = (-9)/2`

`3 y = (-9)/2xx1/3`

`y = (-3)/2`

Therefore, the value of third zero is `(-3)/2`

Hence, the correct alternative is (b).

  Is there an error in this question or solution?
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APPEARS IN

RD Sharma Class 10 Maths
Chapter 2 Polynomials
Q 13 | Page 63
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