# If the Product of Two Zeros of the Polynomial F(X) = 2x3 + 6x2 − 4x + 9 is 3, Then Its Third Zero is - Mathematics

MCQ

If the product of two zeros of the polynomial f(x) = 2x3 + 6x2 − 4x + 9 is 3, then its third zero is

#### Options

• $\frac{3}{2}$

• $- \frac{3}{2}$
• $\frac{9}{2}$
• $- \frac{9}{2}$

#### Solution

Let αβγ  be the zeros of polynomial f(x) = 2x3 + 6x2 − 4x + 9 such that alphabeta=3

We have,

alpha ß y= - (text{coefficient of x})/(text{coefficient of } x^2)

=(-9)/2

Putting alphabeta in alpha beta y, we get

alpha beta y = (-9)/2

3 y = (-9)/2xx1/3

y = (-3)/2

Therefore, the value of third zero is (-3)/2

Hence, the correct alternative is (b).

Is there an error in this question or solution?

#### APPEARS IN

RD Sharma Class 10 Maths
Chapter 2 Polynomials
Q 13 | Page 63