If P (N) is the Statement "2n ≥ 3n" and If P (R) is True, Prove that P (R + 1) is True. - Mathematics

If P (n) is the statement "2n ≥ 3n" and if P (r) is true, prove that P (r + 1) is true.

Solution

We have: $P(n): 2^n \geq 3n$
$\text{ Also } ,$
$P(r) \text{ is true } .$
$\therefore 2^r \geq 3r$
$\text{ To Prove } : P(r + 1)\text{ is true } .$
$\text{ We have } :$
$2^r \geq 3r$
$\Rightarrow 2^r \times 2 \geq 3r \times 2 \left[ \text{ Multiplying both sides by 2 } \right]$
$\Rightarrow 2^{r + 1} \geq 6r$
$\therefore 2^{r + 1} \geq 3r + 3 \left[ 6r \geq 3r + 3 \text{ for every } r \in N . \right]$
$\text{ Hence, P(r + 1) is true } .$

Is there an error in this question or solution?

APPEARS IN

RD Sharma Class 11 Mathematics Textbook
Chapter 12 Mathematical Induction
Exercise 12.1 | Q 3 | Page 3