Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 10th
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If P(A) = 23, P(B) = 25, P(A ∪ B) = 13, then find P(A ∩ B) - Mathematics

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Sum

If P(A) = `2/3`, P(B) = `2/5`, P(A ∪ B) = `1/3`, then find P(A ∩ B)

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Solution

P(A ∪ B) = P(A) + P(B) – P(A ∩ B)

`1/3 = 2/3 + 2/5 - "P"("A" ∩ "B")`

P(A ∩ B) = `2/3 + 2/5 - 1/3`

⇒ `(10 + 6 - 5)/15`

P(A ∩ B) = `11/15`

Concept: Algebra of Events
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APPEARS IN

Tamil Nadu Board Samacheer Kalvi Class 10th SSLC Mathematics Answers Guide
Chapter 8 Statistics and Probability
Exercise 8.4 | Q 1 | Page 330
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