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Sum
If P(A) = `2/3`, P(B) = `2/5`, P(A ∪ B) = `1/3`, then find P(A ∩ B)
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Solution
P(A ∪ B) = P(A) + P(B) – P(A ∩ B)
`1/3 = 2/3 + 2/5 - "P"("A" ∩ "B")`
P(A ∩ B) = `2/3 + 2/5 - 1/3`
⇒ `(10 + 6 - 5)/15`
P(A ∩ B) = `11/15`
Concept: Algebra of Events
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