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Sum

If P(A) = `1/4`, P(B) = `2/5` and P(A ∪ B) = `1/2` Find the value of the following probability: P(A' ∩ B')

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#### Solution

Here, P(A) = `1/4`, P(B) = `2/5` and P(A ∪ B) = `1/2`

P(A' ∩ B') = P(A ∪ B)' .....[De Morgan's law]

= 1 – P(A ∪ B) ...[P(A) = 1 – P(A')]

= `1 - 1/2`

= `1/2`

Concept: Addition Theorem of Probability

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