# If One of Two Identical Slits Producing Interference in Young’S Experiment is Covered with Glass, So that the Light Intensity Passing Through It is Reduced to 50%, Find the Ratio of the Maximum and Minimum Intensity of the Fringe in the Interference Pattern. - Physics

If one of two identical slits producing interference in Young’s experiment is covered with glass, so that the light intensity passing through it is reduced to 50%, find the ratio of the maximum and minimum intensity of the fringe in the interference pattern.

#### Solution

We know that intensity is directly proportional to the square of an amplitude

I prop a^2

if I_1 = I/2

if intensity reduced to 50%, the amplitude will be a/sqrta2

then r = sqrt2

I_"max"/I_"min" = (r+1)^2/(r-1)^2 = (sqrt2 + 1)^2/(sqrt2 - 1)^2

I_"max"/I_"min" = ((2.414)/(0.414))^2 = (5.83)^2

I_"max"/I_"min" = 33.98 ≅ 34

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