Answer 1

Let `alpha and beta`be the roots of quadratic equation`x^2 + ax + 3 =0`in such a way that  `alpha = 1`

Here, a = 1, b = a and ,c = 3

Then , according to question sum of the roots

`alpha + beta = (-b)/ a`

`1 + beta = (-a)/1`

 `beta = -a -1`

And the product of the roots

`alpha . beta = 3/1`

`1 xx beta = 3`

 `beta = 3`

Therefore, value of other root be `beta = 3`.