Tamil Nadu Board of Secondary EducationHSC Arts Class 11th
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If n(P(A)) = 1024, n(A ∪ B) = 15 and n(P(B)) = 32, then find n(A ∩ B) - Mathematics

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Sum

If n(P(A)) = 1024, n(A ∪ B) = 15 and n(P(B)) = 32, then find n(A ∩ B)

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Solution

Given n(P(A)) = 1024, n(A ∪ B) = 15, n(P(B)) = 32

n(P(A)) = 1024 = 210 n(A) = 10

n(P(B)) = 32 = 25 = n(B) = 5

n(A ∪ B) = n(A) + n(B) – n(A ∩ B)

15 = 10 + 5 – n(A ∩ B)

15 = 15 – n(A ∩ B)

n(A ∩ B) = 0

Concept: Cartesian Product
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APPEARS IN

Tamil Nadu Board Samacheer Kalvi Class 11th Mathematics Volume 1 and 2 Answers Guide
Chapter 1 Sets, Relations and Functions
Exercise 1.1 | Q 6 | Page 7
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