Question

If n = 5, `bar(x)` = 6, `sumx^2` = 765, then calculate the coefficient of variation.

Answer 1

Standard deviation (σ) =`sqrt((sumx^2)/"n" - ((sumx)/"n")^2` 

= `sqrt(765/5 - (6)^2`

= `sqrt(153 - 36)`

= `sqrt(117)`

σ = 10.816

Coefficient of variation = `sigma/(barx) xx 100%`

= `10.816/6 xx 100%`

= 180.266%

Coefficient of variation = 180.27%