Maharashtra State BoardHSC Arts 12th Board Exam
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If θ is the measure of acute angle between the pair of lines given by ax2+2hxy+by2=0, then prove that tanθ=∣(2(h2−ab))/(a+b)∣,a+b≠0 - Mathematics and Statistics

Sum

If θ is the measure of acute angle between the pair of lines given by `ax^2+2hxy+by^2=0,` then prove that `tantheta=|(2sqrt(h^2-ab))/(a+b)|,a+bne0`

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Solution

 Let ` m_1 and m_2` be the slopes of the lines represented by the equation

`ax^2+2hxy+by^2=0  .........(1)`

Then their separate equation are

`y=m_1x and y=m_2x`

therefore  their combined equation is

`(y - m_1x)(y - m_2x)=0`

`" i.e " m_1m_2x^2-(m_1+m_2)xy+y^2=0     ..................(2)`

Since (1) and (2) represent the same two lines, comparing the coefficients, we get


`(m_1m_2)/a = 1/b = (m_1+m_2)/(2h) `


`therefore m_1+m_2=-(2h)/b and m_1m_2=a/b`


Thus `(m_1-m_2)^2=(m_1+m_2)^2-4m_1m_2`

 

`(m_1 - m_2)^2 = (- (2h)/b)^2 - 4 (a/b)`


`=(m_1 - m_2)^2 = (4(h^2-ab))/b^2`


Let the angle between y = m1x and y =m2x be θ .

 

`tan theta =|(m_1-m_2)/(1+m_1m_2)|, `

 

`= |(sqrt (m_1 - m_2)^2)/(1 + m_1m_2)|`

 

`=|((4sqrt(h^2-ab))/b^2)/(1+a/b)|,`

 

`therefore tan theta=|(2sqrt(h^2-ab))/(a+b)|,if a + b ne 0`


Hence to proved.

  Is there an error in this question or solution?
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