`barr=(hati-2hatj+3hatk)+lambda(2hati+hatj+2hatk)` is parallel to the plane `barr.(3hati-2hatj+phatk)=10`, find the value of p.
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Solution
`barb=2hati+hatj+2hatk`
`hatn=3hati-2hatj+phatk`
Since, line is parallel to the plane
`bar b.hatn=0`
`(2hati+hatj+2hatk).(3hati-2hatj+phatk)=0`
`(6-2+2p)=0`
`p=-2`
Concept: Plane - Equation of Plane Passing Through the Given Point and Parallel to Two Given Vectors
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