If light of wavelength 412.5 nm is incident on each of the metals given below, which ones will show photoelectric emission and why?
|Metal||Work Function (eV)|
Energy of a photon of the given light is, E = `1240/lambda = 3 ev`
Thus, metals having work-function less than energy of photon of falling light will show photoelectric effect. So, Na and K will show photoelectric effect.