If (k – 3), (2k + l) and (4k + 3) are three consecutive terms of an A.P., find the value of k.
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Solution
(k 3), (2k 1) and (4k 3) are three consecutive terms of an A.P.
⇒ 2(2k + 1) = (k - 3) + (4k + 3)
⇒ 4k + 2 = k - 3 + 4k + 3
⇒ 4k + 2 = 5k
⇒ k = 2
Concept: Nature of Roots
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