Answer 1

Given that,

`h_1:h_2 = 1 : 2 " and " 2pir_1 :2pir_2 = 3 :4`

`i.e., r_1 :r_2 = 3:4`

Therefore,

The ratios of volume of their cones will be

`v_1 : v _2 = 1/3pi r_1^2 h_1 :1/3 pir_2^2 h_2`

    `V_1/V_2 = (1/3 pir_1^2 h_1)/(1/3 pir_1^2 h_2)`

          `=(r_1/r_2)^1 xx (h_1 /h_2)`

        `V_1/V_2 = (3/4)^2 xx (1/2)`

              `=9/32`

    `V_1 :V_2 = 9: 32`