Advertisement Remove all ads

If the Given Figure, Aoc is a Diameter of the Circle and Arc Axb = 1 2 Arc Byc. Find ∠Boc. - Mathematics

Answer in Brief

If the given figure, AOC is a diameter of the circle and arc AXB = \[\frac{1}{2}\] arc BYC. Find ∠BOC.

 
Advertisement Remove all ads

Solution

We need to find  `angle BOC`

\[\text{ arc }  AXB = \frac{1}{2}\text{ arc}  BYC, \]

\[\angle AOB = \frac{1}{2}\angle BOC\]

\[\text{ Also }  \angle AOB + \angle BOC = 180°\] 

\[\text{ Therefore, } \frac{1}{2}\angle BOC + \angle BOC = 180° \]

\[ \Rightarrow \angle BOC = \frac{2}{3} \times 180°= 120°\] 

  Is there an error in this question or solution?
Advertisement Remove all ads

APPEARS IN

RD Sharma Mathematics for Class 9
Chapter 15 Circles
Q 9 | Page 109
Advertisement Remove all ads

Video TutorialsVIEW ALL [1]

Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×