# If the Frequency of Incident Light Falling on a Photosensitive Material is Doubled, Then the Kinetic Energy of the Emitted Photoelectron Will‘Be - Physics

MCQ

If the frequency of incident light falling on a photosensitive material is doubled, then the kinetic energy of the emitted photoelectron will‘be........................................

#### Options

• same as its initial value

• two times its initial value

• more than two times its initial value

• less than two times its initial value

#### Solution

more than two times its initial value

$E={{W}_{0}}+{{K}_{\max }}\Rightarrow {{K}_{\max }}=E-{{W}_{0}}=h\nu -{{W}_{0}}$ $\Rightarrow {{K}_{1}}=h\nu -{{W}_{0}}$ and ${{K}_{2}}=2h\nu -{{W}_{0}}$ $\Rightarrow {{K}_{2}}>2{{K}_{1}}$

Concept: K.E.(Kinetic Energy) and P.E.(Potential Energy) in S.H.M.
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