Question

If the frequency of incident light falling on a photosensitive material is doubled, then the kinetic energy of the emitted photoelectron will‘be........................................

Options

• same as its initial value

• two times its initial value

• more than two times its initial value

• less than two times its initial value

Answer 1

more than two times its initial value

\[E={{W}_{0}}+{{K}_{\max }}\Rightarrow {{K}_{\max }}=E-{{W}_{0}}=h\nu -{{W}_{0}}\] \[\Rightarrow {{K}_{1}}=h\nu -{{W}_{0}}\] and \[{{K}_{2}}=2h\nu -{{W}_{0}}\] \[\Rightarrow {{K}_{2}}>2{{K}_{1}}\]