If figure AB is a chord of the circle and AOC is its diameter such that ∠ACB = 50°. If AT is the tangent to the circle at point A, the ∠BAT is equal to ______
Options
65°
60°
50°
40°
Solution
If figure. AB is a chord of the circle and AOC is its diameter such that ∠ACB = 50°. If AT is the tangent to the circle at point A, the ∠BAT is equal to 50°.
Explanation:
In figure, AOC is a diameter of the circle. We know that, diameter subtends an angle 90° at the circle.
So, ∠ABC = 90°
In ΔACB, ∠A + ∠B + ∠C = 180° .....[Since, sum of all angles of a triangle is 180°]
⇒ ∠A + 90° + 50° = 180°
⇒ ∠A + 140° = 180°
⇒ ∠A = 180° – 140° = 40°
∠A or ∠OAB = 40°
Now, AT is the tangent to the circle at point A, OA is perpendicular to AT.
∴ ∠OAT = 90° ......[From figure]
⇒ ∠OAB + ∠BAT = 90°
On putting ∠OAB = 40°, we get
⇒ ∠BAT = 90° – 40° = 50°
Hence, the value of ∠BAT = 50°.