# If the elevation of the sun changed from 30º to 60º, then find the difference between the lengths of shadows of a pole 15 m high, made at these two positions - Mathematics

Sum

If the elevation of the sun changed from 30º to 60º, then find the difference between the lengths of shadows of a pole 15 m high, made at these two positions

#### Solution

When AB = 15m, θ = 30º,

\text{then }\frac{AC}{AB}=\text{tan}30^\text{o}

\Rightarrow AC=\frac{15}{\sqrt{3}}m.

When AB = 15m, θ = 60º,

\text{then }\frac{AC}{AB}=\text{tan6}0^\text{o}

⇒ AC = 15√3 m.

∴ Diff. in lengths of shadows

=( 15\sqrt{3}-\frac{15}{\sqrt{3}} )

=\frac{30}{\sqrt{3}}=10\sqrt{3}m

Concept: Heights and Distances
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