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MCQ

If each edge of a cuboid of surface area S is doubled, then surface area of the new cuboid is

#### Options

2 S

4 S

6 S

8 S

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#### Solution

Let,

l →Length of the first cuboid

b → Breadth of the first cuboid

h → Height of the first cuboid

And,

L → Length of the new cuboid

B → Breadth of the new cuboid

H → Height of the new cuboid

We know that,

L = 2l

B = 2b

H=2h

Surface area of the first cuboid,

S = 2(lb + bh +hl )

Surface area of the new cuboid,

S' = 2 (LB + BH + HI .)

=2 [(2l)(2b)+(2b)(2h)+(2h)(2l)]

=2 ( 4lb + 4 bh +4hl)

=4[2(lb+bh+hl)]

= 4S

The surface area of the new cuboid is 4S.

Concept: Surface Area of a Cuboid

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