Answer in Brief
If the distance between the foci of a hyperbola is 16 and its ecentricity is \[\sqrt{2}\],then obtain its equation.
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Solution
We have
\[2ae = 16\]
\[ \Rightarrow ae = 8\]
\[ \Rightarrow a = \frac{8}{\sqrt{2}} = 4\sqrt{2}\]
\[ \Rightarrow a^2 = 32\]
Now,
\[\left( ae \right)^2 = a^2 + b^2 \]
\[ \Rightarrow \left( 8 \right)^2 = 32 + b^2 \]
\[ \Rightarrow 64 - 32 = b^2 \]
\[ \Rightarrow b^2 = 32\]
Therefore, the equation of the hyperbola is given by
\[\frac{x^2}{32} - \frac{y^2}{32} = 1\]
\[ \Rightarrow x^2 - y^2 = 32\]
Concept: Hyperbola - Eccentricity
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