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MCQ

If the displacement of an object is proportional to the square of time, then the object is moving with :

#### Options

uniform velocity

uniform acceleration

increasing acceleration

decreasing acceleration

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#### Solution

**uniform acceleration**

We are given with the relationship that,

x = kt^{2}

Differentiating it twice we get,

v = 2kt

a = 2k

Where,

v - velocity

a - acceleration

So, the answer is

(b) Uniform acceleration

Concept: Distance and Displacement

Is there an error in this question or solution?

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