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Sum

If diameter of a road roller is 0.9 m and its length is 1.4 m, how much area of a field will be pressed in its 500 rotations ?

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#### Solution

Length of the road roller, h = 1.4 m

Radius of the road roller, r = `0.9/2` = 0.45 m

Now,

Area of the field pressed in one rotation = Curved surface area of the road roller

= 2πrh

= 2 x `22/7` x 0.45 x 1.4

= 3.96 m^{2}

∴ Area of the field pressed in 500 rotations = 500 × Area of the field pressed in one rotation = 500 × 3.96 = 1980 m^{2}

Thus, the area of the field pressed in 500 rotations is 1980 m^{2}.

Concept: Surface Area of a Cuboid

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