If the Diameter of the Base of a Closed Right Circular Cylinder Be Equal to Its Height H, Then Its Whole Surface Area is - Mathematics

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If the diameter of the base of a closed right circular cylinder be equal to its height h, then its whole surface area is


  • \[2 \pi h^2\]


  • \[\frac{3}{2} \pi h^2\]

  • \[\frac{4}{3} \pi h^2\]


  • \[\pi h^2\]

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Let r be the radius of the cylinder and h be its height.

It is given that:

`2r = h ⇒ r = h/2`

Therefore, total surface area S is:

`S=2pi r^2 + 2 pi r h`

`⇒ S = 2pi r ( r +h)`

`⇒ S = 2pi xx h/2 (h/2 +h)`

`⇒ S = (3pih^2)/2`



Concept: Surface Area of Cylinder
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RD Sharma Mathematics for Class 9
Chapter 19 Surface Areas and Volume of a Circular Cylinder
Exercise 19.4 | Q 10 | Page 29

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