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# If the Diameter of the Base of a Closed Right Circular Cylinder Be Equal to Its Height H, Then Its Whole Surface Area is - Mathematics

MCQ

If the diameter of the base of a closed right circular cylinder be equal to its height h, then its whole surface area is

#### Options

• $2 \pi h^2$

• $\frac{3}{2} \pi h^2$

• $\frac{4}{3} \pi h^2$

• $\pi h^2$

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#### Solution

Let r be the radius of the cylinder and h be its height.

It is given that:

2r = h ⇒ r = h/2

Therefore, total surface area S is:

S=2pi r^2 + 2 pi r h

⇒ S = 2pi r ( r +h)

⇒ S = 2pi xx h/2 (h/2 +h)

⇒ S = (3pih^2)/2

Is there an error in this question or solution?
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#### APPEARS IN

RD Sharma Mathematics for Class 9
Chapter 19 Surface Areas and Volume of a Circular Cylinder
Q 10 | Page 29
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