If a Cos θ + B Sin θ = M and a Sin θ – B Cos θ = N, Prove that A2 + B2 = M2 + N2 - Mathematics

If a cos θ + b sin θ = m and a sin θ – b cos θ = n, prove that a² + b² = m² + n²

R.H.S `m^2 sin^2 theta`

`= (a cos theta + b sin theta)^2 + (a sin theta - b cos theta)^2`

`= a^2 cos^2 theta + b^2 sin^2 theta + 2 ab sin theta cos theta + a^2 sin^2 theta + b^2 cos^2 theta - 2 ab sin theta cos theta`

`= a^2 cos^2 theta + b^2 cos^2 theta + b^2 sin^2 theta + a^2 sin^2 theta`

`= a^2(sin^2 theta + cos^2 theta) + b^2(sin^2 theta + cos^2 theta)`

`=a^2 + b^2` (∵ `sin^2 theta + cos^2 theta = 1`)

Is there an error in this question or solution?

Chapter 11 Trigonometric Identities
Exercise 11.1 | Q 80 | Page 47