Maharashtra State BoardSSC (English Medium) 9th Standard
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If Cos θ = 15 17 Then Find Sin θ - Geometry

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Sum

If cos θ = `15/17` then find sin θ

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Solution

sin2θ + cos2θ = 1

⇒ sin2θ + `(15/17)^2 `= 1                                 `( cos θ = 15/17)`

⇒ sin2θ + `225/289` = 1 

⇒ sin2θ = 1 - `225/289`

⇒ sin2θ = `(289 - 225)/289 = 64/289` 

⇒ sin θ = `sqrt (64/289) = sqrt (8/17)^2`

⇒ sin θ = `8/17`

Thus, the value of sin θ is `8/17`.

Concept: Important Equation in Trigonometry
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APPEARS IN

Balbharati Mathematics 2 Geometry 9th Standard Maharashtra State Board
Chapter 8 Trigonometry
Practice Set 8.2 | Q 4 | Page 112
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