Short Note

Sum

If a bus travelling at 20 m/s is subjected to a steady deceleration of 5 m/s^{2}, how long will it take to come to rest ?

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#### Solution

We have to find the time taken to reach the given final velocity.

We have:

Initial velocity (u) = 20 m/s

Final velocity (v) = 0 m/s

Acceleration for the entire journey (a) = –5 ms^{2}.

Let the time taken be (t).

We can calculate the time taken using the first equation of motion.

`t = (v-u)/a`

Time taken by the bus to come to rest:

= `(0-20)/-5`

= 4 s

Concept: Measuring the Rate of Motion - Speed with Direction

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