Advertisement Remove all ads

If Ax = By = Cz And B2 = Ac, Prove That : Y = 2az/X + Z - Mathematics

Sum

If ax = by = cz and b2 = ac, prove that : y = `[2az]/[x + z]`

Advertisement Remove all ads

Solution

Let ax = by = cz = k
∴ a = `k^(1/x) ; b = k^(1/y) ; c = k^(1/z)`

Also, We have b2 = ac 
∴ `( k^(1/y))^2 = ( k^(1/x)) xx ( k^(1/2))` 

⇒ `k^(2/y) = k^( 1/x + 1/z )`

⇒ `k^(2/y) = k^[ z + x ]/[  xz ]`

Comparing the powers we have
`2/y = [ z + x ]/[ xz ]`

⇒ `y = [ 2 xz ]/[ z + x ]`

Concept: Solving Exponential Equations
  Is there an error in this question or solution?
Advertisement Remove all ads

APPEARS IN

Selina Concise Mathematics Class 9 ICSE
Chapter 7 Indices (Exponents)
Exercise 7 (B) | Q 9 | Page 100
Advertisement Remove all ads
Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×