MCQ

If ABC and DEF are two triangles such that ΔABC \[\cong\] ΔFDE and AB = 5cm, ∠B = 40°

#### Options

DF = 5cm, ∠F = 60°

DE = 5cm, ∠E = 60°

DF = 5cm, ∠E = 60°

DE = 5cm, ∠D = 40°

Advertisement Remove all ads

#### Solution

It is given that ΔABC \[\cong\] ΔFDE and AB = 5 CM . ∠B = 40 , and ∠A = 80°

So AB = FD and ∠C = ∠E

Now, in triangle ABC,

∠A +∠B +∠C = 180°

⇒ 80 + 40 + ∠C = 180°

⇒ ∠C = 60°

Therefore,

DF = 5cm, ∠E = 60°

Concept: Congruence of Triangles

Is there an error in this question or solution?

Advertisement Remove all ads

#### APPEARS IN

Advertisement Remove all ads

Advertisement Remove all ads