Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 10th
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If A and B are two mutually exclusive events of a random experiment and P(not A) = 0.45, P(A ∪ B) = 0.65, then find P(B). - Mathematics

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Sum

If A and B are two mutually exclusive events of a random experiment and P(not A) = 0.45, P(A ∪ B) = 0.65, then find P(B).

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Solution

P(not A) = 0.45

1 – P(A) = 0.45

P(A) = 1 – 0.45 = 0.55

P(A ∪ B) = P(A) + P(B)

0.65 = 0.55 + P(B)

0.65 – 0.55 = P(B)

0.10 = P(B)

P(B) = 0.1

Concept: Algebra of Events
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APPEARS IN

Tamil Nadu Board Samacheer Kalvi Class 10th SSLC Mathematics Answers Guide
Chapter 8 Statistics and Probability
Exercise 8.4 | Q 3 | Page 330
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