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Sum
If A and B are two mutually exclusive events of a random experiment and P(not A) = 0.45, P(A ∪ B) = 0.65, then find P(B).
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Solution
P(not A) = 0.45
1 – P(A) = 0.45
P(A) = 1 – 0.45 = 0.55
P(A ∪ B) = P(A) + P(B)
0.65 = 0.55 + P(B)
0.65 – 0.55 = P(B)
0.10 = P(B)
P(B) = 0.1
Concept: Algebra of Events
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