# If 6 Men and 8 Boys Can Do a Piece of Work in 10 Days While 26 Men and 48 Boys Can Do the Same Work in 2 Days, the Time Taken by 15 Men and 20 Boys in Doing the Same Type of Work Will Be - Mathematics

MCQ

If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same work in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be

• 4 days

• 5 days

• 6 days

• 7 days

#### Solution

4 days
Explanation:
Let 1 man's 1 day's work = x
and 1 boy's 1 day's work = y

Then, 6x+8y=1/10

and 26x+48y=1/2

Solving these two equations, we get

x=1/100

and y=1/200

(15 men + 20 boy)'s 1 day's work

= (15/100+20/200)=1/4

∴ 15 men and 20 boys can do the work in 4 days.

Concept: Time and Work (Entrance Exam)
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