If 49392 = a4b2c3, find the values of a, b and c, where a, b and c are different positive primes.
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Solution
First find out the prime factorisation of 49392.
It can be observed that 49392 can be written as `2^4xx3^2xx7^3,` where 2, 3 and 7 are positive primes.
`therefore49392=2^4 3^2 7^3=a^4b^2c^3`
⇒ a = 2, b = 3, c = 7
Concept: Laws of Exponents for Real Numbers
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