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# If 4 5 , a, 2 are three consecutive terms of an A.P., then find the value of a. - Mathematics

Sum

If 4/5 , a, 2 are three consecutive terms of an A.P., then find the value of a

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#### Solution

Here, we are given three consecutive terms of an A.P.

First term (a1) =  4/5

Second term (a2) = a

Third term (a3) =  2

We need to find the value of a. So, in an A.P. the difference of two adjacent terms is always constant. So, we get,

d = a2 - a

d = a - 4/5                      ................(1)

Also,

d = a3 - a2

d = 2 -a                        ...................(2)

Now, on equating (1) and (2), we get,

a - 4/5 = 2 - a

 a + a = 2 +4/5

2a = (10 + 4)/5

a = 14/10

a = 7/5

Therefore,  a = 7/5

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#### APPEARS IN

RD Sharma Class 10 Maths
Chapter 5 Arithmetic Progression
Q 14 | Page 56
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