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If 3 Cot θ = 2, Find the Value of `(4sin Theta - 3 Cos Theta)/(2 Sin Theta + 6sin Theta)` - Mathematics

If 3 cot θ = 2, find the value of `(4sin theta - 3 cos theta)/(2 sin theta + 6sin theta)`

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Solution

`cot theta = 2/3`

`= ((4 sin theta - 3 cos theta)/sin theta)/((2sin theta + 6 cos theta)/sin theta)`

`= (4 - 3 cot theta)/(2 + 6 cot theta)`

`= (4 - 3 xx 2/3)/(2 + 6 xx 2/3)`

`= (4 + 2)/(2 + 4) = 2/6`

`= 1/3`

 

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APPEARS IN

RD Sharma Class 10 Maths
Chapter 10 Trigonometric Ratios
Exercise 10.1 | Q 11 | Page 24
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