MCQ

If θ and 2θ − 45° are acute angles such that sin θ = cos (2θ − 45°), then tan θ is equal to

#### Options

1

−1

\[\sqrt{3}\]

\[\frac{1}{\sqrt{3}}\]

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#### Solution

Given that: sin θ=cos (20-45°) and θ and 2θ-45 are acute angle

We have to find tan θ

⇒` sin θ=cos (2θ-45°)`

⇒`90°-θ=2θ-45θ`

⇒`3θ=135°`

Where θ and` 2θ-45°` are acute angles

Since `θ =45°`

Now

tan θ

= tan 45° Put θ=45°

=1

Is there an error in this question or solution?

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