# If √ 2 = 1 . 414 , Then the Value of √ 6 − √ 3 Upto Three Places of Decimal is - Mathematics

MCQ

If $\sqrt{2} = 1 . 414,$ then the value of $\sqrt{6} - \sqrt{3}$ upto three places of decimal is

•  0.235

• 0.707

• 1.414

• 0.471

#### Solution

Given thatsqrt2 = 1.414 .We need to find sqrt6 - sqrt3.

We can factor out from the given expression, to get

sqrt6 - sqrt3 = sqrt3(sqrt2 - 1).

Putting the value ofsqrt2, we get

sqrt3 (sqrt2-1) = sqrt3(1.4142 - 1)

=1.732xx0.4142

= 0.7174

Hence the value of expression must closely resemble be0.707.

Concept: Laws of Exponents for Real Numbers
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#### APPEARS IN

RD Sharma Mathematics for Class 9
Chapter 3 Rationalisation
Exercise 3.4 | Q 22 | Page 18

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