If √ 2 = 1 . 414 , Then the Value of √ 6 − √ 3 Upto Three Places of Decimal is - Mathematics

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MCQ

If \[\sqrt{2} = 1 . 414,\] then the value of \[\sqrt{6} - \sqrt{3}\] upto three places of decimal is

Options

  •  0.235

  • 0.707

  • 1.414

  • 0.471

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Solution

Given that`sqrt2 = 1.414` .We need to find `sqrt6 - sqrt3`.

We can factor out from the given expression, to get

 `sqrt6 - sqrt3 = sqrt3(sqrt2 - 1)`.

Putting the value of`sqrt2`, we get

`sqrt3 (sqrt2-1) = sqrt3(1.4142 - 1)`

                      `=1.732xx0.4142`

                      `= 0.7174`

Hence the value of expression must closely resemble be`0.707.`

Concept: Laws of Exponents for Real Numbers
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APPEARS IN

RD Sharma Mathematics for Class 9
Chapter 3 Rationalisation
Exercise 3.4 | Q 22 | Page 18

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