Advertisement Remove all ads

If 1 Gram of Sulphur Dioxide Contains X Molecules, How Many Molecules Will Be Present in 1 Gram of Oxygen ? (S = 32 U ; O = 16 U) - Science

Advertisement Remove all ads
Advertisement Remove all ads
Advertisement Remove all ads
Answer in Brief

If 1 gram of sulphur dioxide contains x molecules, how many molecules will be present in 1 gram of oxygen ?

(S = 32 u ; O = 16 u)

Advertisement Remove all ads

Solution

Given:

Mass of sulphur dioxide = 1g

We know that equal moles of all substances contain equal number of molecules. (1 mole of all substances contains 6.022 × 1023 molecules).

Therefore, the ratio of molecules in sulphur dioxide and oxygen will be same as the ratio of their moles.

Number of moles in 1g of sulphur dioxide:

1 mole of SO2 = (1 × 32) + (2 × 16) = 64g

64g of SO2 = 1 mole of SO2

Therefore, 1g of SO2 = 1/64 moles of SO2

Now, 1/64 moles of SO2 contain x molecules (given). Since equal number of molecules are present in equal moles of all substances, 1/64 moles of oxygen will also contain x number of molecules.
Number of moles in 1g of oxygen:

1 mole of O2 = 2 × 16 = 32g32g of O2 = 1 mole of O2
Therefore, 1g of O2 = 1/32 moles of O2

We have already stated that 1/64 moles of oxygen contain x molecules. Therefore, 1/32 mole of oxygen will contain = x × 64 / 32 = 2x

Hence, 1 gm of oxygen consists of 2x number of molecules.

Concept: Molecules
  Is there an error in this question or solution?

APPEARS IN

Lakhmir Singh Class 9 Chemistry - Science Part 2
Chapter 3 Atoms and Molecules
Hots Questions | Q 43 | Page 174

Video TutorialsVIEW ALL [1]

Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×