Answer 1

\[2 {KClO}_3 \left( s \right) \to^∆ 2KCl\left( s \right) + 3 O_2 \uparrow\]

Heat is given in the product side to break the compound into simpler substances, as it mentioned in the above reaction. So, It is an endothermic reaction because heat is supplied in an exothermic reaction.