#### Question

Calculate the total number of electrons present in 1.4 g of dinitrogen gas.

#### Solution 1

Molecular mass of N_{2 }= 28g

28 g of N_{2} has No. of molecules = 6.022 x 10^{23} 1.4 g of

N_{2} has No. of molecules = 6.022 x 10^{23} x 1.4 g/28 g

= 3.011 x 10^{22} molecules.

Atomic No. of Nitrogen (N) = 7

1 molecule of N_{2} has electrons = 7 x 2 = 14

3.011 x 10^{22} molecules of N_{2} have electrons

= 14 x 3.011 x 10^{22}

= 4.215 x 10^{23} electrons.

#### Solution 2

Molar mass of dinitrogen (N_{2}) = 28 g mol^{–1}

Thus, 1.4 g of `N_2 = 1.4/28 = 0.05 mol`

`= 0.05 xx 6.02 xx 10^(23) " number of molecules"`

`= 3.01 xx 10^23` number of molcules

Now, 1 molecule of `N_2` contains 14 electrons.

Therefore, 3.01 × 10^{23} molecules of N_{2} contains = 1.4 × 3.01 × 10^{23}

= 4.214 × 10^{23} electrons

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Solution Calculate the Total Number of Electrons Present in 1.4 G of Dinitrogen Gas. Concept: Ideal Gas Equation - Density and Molar Mass of a Gaseous Substance.