CBSE (Science) Class 11CBSE
Share
Notifications

View all notifications

Calculate the Total Number of Electrons Present in 1.4 G of Dinitrogen Gas. - CBSE (Science) Class 11 - Chemistry

Login
Create free account


      Forgot password?

Question

Calculate the total number of electrons present in 1.4 g of dinitrogen gas.

Solution 1

Molecular mass of N= 28g

28 g of N2 has No. of molecules = 6.022 x 1023 1.4 g of

N2 has No. of molecules = 6.022 x 1023 x 1.4 g/28 g

= 3.011 x 1022 molecules.

Atomic No. of Nitrogen (N) = 7

1 molecule of N2 has electrons = 7 x 2 = 14

3.011 x 1022 molecules of N2 have electrons

= 14 x 3.011 x 1022

= 4.215 x 1023 electrons.

Solution 2

Molar mass of dinitrogen (N2) = 28 g mol–1

Thus, 1.4 g of `N_2 = 1.4/28 = 0.05 mol`

`= 0.05 xx 6.02 xx 10^(23) " number of molecules"`

`= 3.01 xx 10^23` number of molcules

Now, 1 molecule of `N_2` contains 14 electrons.

Therefore, 3.01 × 1023 molecules of N2 contains = 1.4 × 3.01 × 1023

= 4.214 × 1023 electrons

  Is there an error in this question or solution?

APPEARS IN

Solution Calculate the Total Number of Electrons Present in 1.4 G of Dinitrogen Gas. Concept: Ideal Gas Equation - Density and Molar Mass of a Gaseous Substance.
S
View in app×