Advertisement Remove all ads

How Much is this Distance in Terms of Parsecs? How Much Parallax Would this Star (Named Alpha Centauri) Show When Viewed from Two Locations of the Earth Six Months Apart in Its Orbit Around the Sun - Physics

The nearest star to our solar system is 4.29 light years away. How much is this distance in terms of parsecs? How much parallax would this star (named Alpha Centauri) show when viewed from two locations of the Earth six months apart in its orbit around the Sun?

Advertisement Remove all ads

Solution

Distance of the star from the solar system = 4.29 ly

1 light year is the distance travelled by light in one year.

1 light year = Speed of light × 1 year

= 3 × 108 × 365 × 24 × 60 × 60 = 94608 × 1011 m

∴4.29 ly = 405868.32 × 1011 m

∵1 parsec = 3.08 × 1016 m

:. 4.29 ly = `(405868.32 xx 10^(11))/(3.08xx 10^(16))`

Using the relation.

`theta = d/D`

where

Diameter of Earth's orbit, `d = 3 xx 10^(11) m`

Distance of the star from the Earth, D = `405868.32 xx 10^(11) m`

`:. theta = (3 xx 10^(11))/(405868.32xx 10^(11)) = 7.39 xx 10^(-6) rad`

But, 1 sec = 4.85 × 10–6 rad

`:. 7.39 xx 10^(-6) rad = (7.39 xx 10^(-6))/(4.85xx10^(-6)) = 1.52`

  Is there an error in this question or solution?
Advertisement Remove all ads

APPEARS IN

NCERT Class 11 Physics Textbook
Chapter 2 Units and Measurements
Q null
Advertisement Remove all ads
Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×