How many two-digit numbers are divisible by 5? Activity :- Two-digit numbers divisible by 5 are, 10, 15, 20, ......, 95. Here, d = 5, therefore this sequence is an A.P. Here, a = 10, d = 5, tn = 9 - Algebra

Sum

How many two-digit numbers are divisible by 5?

Activity :-  Two-digit numbers divisible by 5 are, 10, 15, 20, ......, 95.

Here, d = 5, therefore this sequence is an A.P.

Here, a = 10, d = 5, tn = 95, n = ?

tn = a + (n − 1) square

square = 10 + (n – 1) × 5

square = (n – 1) × 5

square = (n – 1)

Therefore n = square

There are square two-digit numbers divisible by 5

Solution

Two-digit numbers divisible by 5 are, 10, 15, 20, ......, 95.

Here, d = 5, therefore this sequence is an A.P.

Here, a = 10, d = 5, tn = 95, n = ?

tn = a + (n − 1) d

∴ 95 = 10 + (n – 1) × 5

∴ 95 – 10 = (n – 1) × 5

∴ 85 = (n – 1) × 5

∴ 85/5 = (n – 1)

∴ 17 = (n – 1)

∴ n = 17 + 1

Therefore n = 18

There are 18 two-digit numbers divisible by 5

Concept: General Term of an Arithmetic Progression
Is there an error in this question or solution?